Question

calculate the work done in taking a charge of 1 microcoulomb in a uniform electric field of 10 Newton per coulomb from b to c. given ab is equals to 5 cm along the field and ac is equal to 10cm perpendicular to the field​

Answer 1

Given: A charge of 1 micro coulomb in a uniform electric field of 10 Newton per coulomb, AB is equals to 5 cm along the field and AC is equal to 10 cm perpendicular to the field​.

To find: Calculate the work done?

Solution:

• Now we know, Work Done = F.S cos theta

• For the path AB, we have:

                W(AB) = FS cos 0

                            = FS

                            = qE x S

                            = 10^-6 x 10 x 5 x 10^-2 J

                            = 50 x 10^-8 J

• Now:

                W(CA) = FS cos 90

                            = FS x 0            

                W(CA) = 0

• So now:

                W(BC) = -W(CB)

                            = (W(AB) + W(CA))

                W(BC) = -50 X 10^-8 J

Answer:

               So the work done is  -50 X 10^-8 J.