Question

calculate the work done in the process​

Answer 1

Answer:

The process A - B is isobaric. Therefore work done is given by, WAB = P. ∆V = 200 × 103 × (5-3) × 10-3 = 400J ∴ Also, work done is given by area under the curve, AB. Area = (AB) × (200) × 103 = (2 × 10-3) × 200 × 103 =400 ∴ Area = WAB. 2. Work done in the process BC, WBC = Area under the curve BC = 0 3. Work done in process CA, WCA= - (Area under the curve CA) ∴ WCA = - [ 1 2 12 × (100 + 200) × 103 × (2 × 10-3)] ∴ WCA = - 300 J

∴ Total work done by the gas at the end of cycle, Wtotal = (400 + 0 - 300) J = 100 J

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