calculate the work done required to be done to stop a car of 1500kg moving at a velocity of 60 km per hour
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m=1500kg
u= 60km/h =60* 5/18 = 50/3m/s
v =0m/s
w = change in its KE.
initial KE =1/2 mu2
final KE=1/2mv²
w = 1/2mv2 - 1/2 mu2
=1/2m(v2-u2)
= 1/2 * 15000{0- (50/3)2}
= -208333.33J
u= 60km/h =60* 5/18 = 50/3m/s
v =0m/s
w = change in its KE.
initial KE =1/2 mu2
final KE=1/2mv²
w = 1/2mv2 - 1/2 mu2
=1/2m(v2-u2)
= 1/2 * 15000{0- (50/3)2}
= -208333.33J
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i write everything in above photo
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