calculate the work done required to stop a car of 1500kg at a speed of 60km/h
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work done = potential energy it possesses
law of conservation of energy,
kinetic energy= potential energy
p.e.=1/2×1500×(50/3)×(50/3)
=2.8×10^5j
work done =p.e.
=2.8×10^5 j
law of conservation of energy,
kinetic energy= potential energy
p.e.=1/2×1500×(50/3)×(50/3)
=2.8×10^5j
work done =p.e.
=2.8×10^5 j
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