Physics, asked by ExclusiveCouple, 1 month ago

Calculate the work done required to stop a car of mass 50 kg moving with a velocity of 54 km/hr.​

Answers

Answered by ItzBlinkingstar
1

Answer:

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Mass of the car =50 kg

intial velocity = 54 km /h

work done to step car?

(Continuous you can see in attachment)

Attachments:
Answered by OoINTROVERToO
3

 \bf{ \pmb{ \gray { \underline{GIVEN }}}} \\ \tt{ Mass  \: of \:  a \:  body  \: → \:  50kg }\\  \tt \: Velocity \:  of  \: body  \: →  \: 54km/hr  \\ \\ \bf{ \pmb{  \gray{ \underline{ TO \:  \:  FIND  }}}}\\  \tt \:  \blue{Work \:  done \:  by  \: body} \\  \\  \bf{ \pmb{ \gray{ \underline{SOLUTION}}}} \\  \small{ \sf \: According \:  to  \: Work \:  Energy  \: Theorem :−} \\  \\ \begin{gathered}\sf\red{ \boxed{ \bf Work \ Done = \Delta Energy_{Kinetic\ energy} } }\\\\\rm  \small\: Work \ Done = \dfrac{1}{2}mv^2- \dfrac{1}{2}mu^2 \\\\\rm  \small \: Work \ Done = \dfrac{1}{2}m ( v^2 - u^2 ) \\\\\rm \small Work \ Done = \dfrac{1}{2}\times 50kg [ (0m/s)^2 - (54km/hr)^2 ] \\\\\rm \small Work \ Done = 25kg \bigg\lgroup 0m^2/s^2 - \bigg(54 \times \dfrac{5}{18}m/s.\bigg)^2 \bigg\rgroup \\\\\rm  \small \: Work \ Done = 25kg [ 0m^2/s^2 - (15m/s)^2 ] \\\\\rm   \small \: Work \ Done = 25kg \times - 225 m^2/s^2 \\\\ \large \boxed{\blue{\mathbb {WORK \ DONE = -5625 \ JOULES .} }}\end{gathered}

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