calculate the work done to stop a car of 1500kg with velocity 60km/hr
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Mass of the car m = 1500 kg
Velocity of the car v = 60 km/h
= 60×1000 /60×60 = 50 /3 m/s
The car is in motion, so its energy = kinetic energy = 1 /2 mv2
= 1 /2 (1500) ( 50/ 3 ) 2 J
= 1/ 2 × (1500) × 2500/ 9 J
= 208333.3 J
The kinetic energy of the car, when it comes to rest = 0 J
Work done on object = change in kinetic energy
= 208333.3 − 0 J
= 208333.3 J
Hence, the work required to stop the car is 208333.3 J
Hope it will help you.
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Velocity of the car v = 60 km/h
= 60×1000 /60×60 = 50 /3 m/s
The car is in motion, so its energy = kinetic energy = 1 /2 mv2
= 1 /2 (1500) ( 50/ 3 ) 2 J
= 1/ 2 × (1500) × 2500/ 9 J
= 208333.3 J
The kinetic energy of the car, when it comes to rest = 0 J
Work done on object = change in kinetic energy
= 208333.3 − 0 J
= 208333.3 J
Hence, the work required to stop the car is 208333.3 J
Hope it will help you.
Mark as brainliest........
pranavganesh90:
Thanks my mahn
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