CALCULATE THE WORK DONE TO STOP A TRUCK OF 3000 KG MOVING AT A VELOCITY OF 100 KM /H
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First of all let us convert the speed into m/s
100 km/h = 100 × 5/18 = 250/9 m/s
So, we have to calculate the work done in order to stop the truck moving with a velocity of 250/9 m/s
Work done = Change in kinetic energy
= Kinetic energy (final) - Kinetic energy (initial)
Since, the body will stop at last, its final kinetic energy = 0 J
Initial kinetic energy = 1/2 mv²
= 1/2 × 3000 × 250/9
= 1500 × 250/9
= 500 × 250/3
= 1,25,000/3 Joules
So, work done = 0 - 125000/3
=> Work done = - 1,25,000/3 Joules
Negative sign indicates that the work is done in the opposite side of motion.
100 km/h = 100 × 5/18 = 250/9 m/s
So, we have to calculate the work done in order to stop the truck moving with a velocity of 250/9 m/s
Work done = Change in kinetic energy
= Kinetic energy (final) - Kinetic energy (initial)
Since, the body will stop at last, its final kinetic energy = 0 J
Initial kinetic energy = 1/2 mv²
= 1/2 × 3000 × 250/9
= 1500 × 250/9
= 500 × 250/3
= 1,25,000/3 Joules
So, work done = 0 - 125000/3
=> Work done = - 1,25,000/3 Joules
Negative sign indicates that the work is done in the opposite side of motion.
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