Question

Calculate the work done when 156 g potassium reacts with water in an open container of water at 300 K.​

Answer 1

Answer:

See the attachment.. It may help you

Answer 2

Work done when 156 g potassium reacts with water in an open container of water at 300 K is 9976.8 J.

Explanation:

The given data is as follows.

        mass = 156 g,   molar mass of K = 39 g/mol

           T = 300 K

First, we will calculate the number of moles of potassium as follows.

          No. of moles = $\frac{\text{mass}}{\text{molar mass}}$

                                = $\frac{156 g}{39 g/mol}$

                                = 4 mol

The relation between work, number of moles and temperature is as follows.

                      W = -nRT

                          = $-4 mol \times 8.314 J/mol \times 300 K$

                          = -9976.8 J

Therefore, work done when 156 g potassium reacts with water in an open container of water at 300 K is 9976.8 J.

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