calculate the work done when 2 moles of an idea gas expands reversiply and isothermally from a volume of 500 ml to a volume of 2l at 25 degree c and normal pressure
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Answer:
n = 2 moles
vi = 500 ml = 0.5 ltr
vf = 2 ltr
T = 25°c =298 k
w = -2.303 nRT log ( v/vi)
w = -2.303 × 2 × 8.314 × 298 × log 2/0.5
w = -2.303 × 2 × 8.314 × 298 × log ( 4 )
w = -2.303 × 2 × 8.314 × 298 × 0.6021
w = -6871 J
w = -6.871 kJ
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