Question

calculate the work done when a force of 30N moves a body by 8m in it's direction
what type of work is done ​

Answer 1

Answer:

$f = 30 \: newton$

$d = 8m$

$work \: done = f \times d$

$w = 30 \times 8$

$= 240 \: joule.$

Explanation:

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