Question

calculate the work done when a mass of 20kg is lifted through a Vertical distance of 200cm take g=10m/s.

Answer 1

Explanation:

W= f. x. M=20kg, X= 200cm= 2m g=10m/s^2

w= mgcos0×x

w= 20×10×1×2

w= 400jule

Answer 2

Given :-

Mass = 20 kg

Height lifted = 200 cm

To Find :-

The work done.

Analysis :-

Here we are given with the mass and the height.

In order to find the work done substitute the given values from the questions accordingly such that work done is equal to mass into gravity into height.

Solution :-

We know that,

• m = Mass
• w = Work done
• g = Gravity
• h = Height

Using the formula,

$\underline{\boxed{\sf Potential \ energy=Mass \times Gravity \times Height}}$

Given that,

Mass (m) = 20 kg

Gravity (g) = 10 m/s

Height (h) = 200 cm = 2 m

Substituting their values,

⇒ w = mgh

⇒ w = 20 × 10 × 2

⇒ w = 200 × 2

⇒ w = 400 J

Therefore, the work done is 400 J.