Question

Calculate the work done when an ideal gas is compressed isothermal by 1000 ml against a constant atmospheric pressure​

Answer 1

Answer:

w= 101.3 J

Explanation:

v=1000ml = 1L

1 atm = 101.3

w= Pext × v

=101.3 × 1

= 101.3 J

Answer 2

$W=101.325\ J$ is the work done in the process.

Explanation:

Given:

change in volume, $dV=1000\ mL=10^{-3}\ m^3$

pressure of the gas, $P=101325\ Pa$

Now the work done in compressing the gas:

$W=P.dV$

$W=101325\times 10^{-3}$

$W=101.325\ J$

The above process is isobaric since it occurs at a constant pressure which is atmospheric pressure.

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TOPIC: isobaric work

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