Question

calculate the work done when pressure of 2 mole of an ideal gas is doubled at 300 k​

Answer 1

Answer:

Amount of work done in reversible isothermal expansion,

w=−2.303nRTlog

V

1

V

2

given, n=2,R=8.314JK

−1

mol

−1

,T=298K,V

2

=20L and V

1

=10L

Substituting the values in above equation

w=−2.303×2×8.314×298×log

10

20

w=−2.303×2×8.314×298×0.3010=−3434.9J

i.e., work done by the system

Explanation:

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