Question

Calculate the work done while lifting 300 kg of water through a vertical height of 6 cm. g =10m/s²

Answer 1

Answer:

18,000

Explanation:

w=mgh

mass=300kg

height:6m

gravity:10m/s square

mgh=300*6*10

=18,000

hope That it will help u.

Answer 2

Given that,

• Mass, m = 300kg
• Height, h = 6cm
• Acceleration due to gravity, g = 10m/s²

We know that,

• W = mgh

Substituting the values,

→ W = 300 × 10 × 6

→ W = 300 × 60

→ W = 18000 J

Therefore, the work done is 18000 joules.