Question

Calculate the work function of the metal when the threshold wavelength is 270 nm. a) 2eV b) 9eV c) 1 eV d) 4.6 ev

Answer 1

Explanation:

E = hf

= (6.626×10^-34)×(3×10^8)/270×10^-9

= 19.878×10^-19/2.7

= 7.3× 10^-19J

= 7.3×6.242×10^-19×10^18

= 45.95×10^-¹

E = 4.6eV

option d(4.6eV) is right answer