Chemistry, asked by Swetlani2111, 5 hours ago

Calculate the work obtained in 1000 cycles of a reversible engine operating between 1000K and 300K if heat absorbed at higher temperature is 2.1kJ/cycle

Answers

Answered by facebookyadav8
0

Answer:

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Answered by ishwaryam062001
0

Answer:

The work obtained in 1000 cycles is therefore 2100 kJ.

Explanation:

From the above question,

They have given :

The work obtained by a reversible engine operating between two temperatures is calculated by multiplying the heat absorbed at the higher temperature with the number of cycles.

In this case, the engine is operating between 1000K and 300K and the heat absorbed at the higher temperature is 2.1kJ/cycle. The work obtained in 1000 cycles is therefore 2100 kJ.

Work obtained = 2.1 kJ/cycle x 1000 cycles

                         = 2100 kJ

To calculate the heat absorbed at the higher temperature:

Heat absorbed = 2.1 kJ/cycle

The work obtained in 1000 cycles:

Work obtained = Heat absorbed x Number of cycles

                         = 2.1 kJ/cycle x 1000 cycles

                         = 2100 kJ

The work obtained in a reversible engine operating between two temperatures is the product of the heat absorbed at the higher temperature and the number of cycles.

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