Calculate the work required to be done stop a car of 1200 kg moving with a vilocity of 54km hour
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Given,
mass of the object = 1200 kg
velocity= 54km/hr=15m/s
work done here is in the form of kinetic energy.
so, work done = 1/2mv^2
=1/2 x 1200 x( 15m/s)^2
=600 x 225 m/s^2
= 135000Joules.
hope it helps u.......
mass of the object = 1200 kg
velocity= 54km/hr=15m/s
work done here is in the form of kinetic energy.
so, work done = 1/2mv^2
=1/2 x 1200 x( 15m/s)^2
=600 x 225 m/s^2
= 135000Joules.
hope it helps u.......
Ankit1234:
hey! It's "mv^2"
Answered by
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Mass of car = 1200 kg
Velocity = 54km/h
= 15m/s
Work done = K.E. of the car
= 1/2 x mv²
= 1/2 x 1200 x (15ms^-1)²
= 1/2 x 1200 x 225 m²s-²
= 135000 joules.
Velocity = 54km/h
= 15m/s
Work done = K.E. of the car
= 1/2 x mv²
= 1/2 x 1200 x (15ms^-1)²
= 1/2 x 1200 x 225 m²s-²
= 135000 joules.
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