Question

Calculate the work required to be done to stop a
bus of mass 2000 kg moving at a velocity of
36km/h​

Answer 1

Answer:

2 × 10^5 Joule is the work required to be done to stop a bus of mass 2000 kg moving at a velocity of

36km/h

Explanation:

Given,

m = 2000 kg

v = 36 km/h

v = 36 × 1000/3600 m/s

v = 36 × 10/36 m/s

v = 10 m/s

Work done = Fs

Work done = mas

Work done = msv/t

Work done = mv.v [ v = s/t ]

Work done = mv^2

Work done = 2000 × (10)^2 Joule

Work done = 2000 × 100 Joule

Work done = 2,00,000 Joule

Work done = 2 × 10^5 Joule

Here,

m is the mass of bus

v is the velocity of bus

s is the distance travelled by the bus

t is the time taken by bus

Hence,

2 × 10 ^5 joules is the work required to be done to stop a bus of mass 2000 kg moving at a velocity of

is the work required to be done to stop a bus of mass 2000 kg moving at a velocity of36km/h.

Answer 2

Answer:

-10^5

Explanation:

here's the answer to your question