Calculate the work required to be done to stop a
bus of mass 2000 kg moving at a velocity of
36km/h
Answers
Answer:
2 × 10^5 Joule is the work required to be done to stop a bus of mass 2000 kg moving at a velocity of
36km/h
Explanation:
Given,
m = 2000 kg
v = 36 km/h
v = 36 × 1000/3600 m/s
v = 36 × 10/36 m/s
v = 10 m/s
Work done = Fs
Work done = mas
Work done = msv/t
Work done = mv.v [ v = s/t ]
Work done = mv^2
Work done = 2000 × (10)^2 Joule
Work done = 2000 × 100 Joule
Work done = 2,00,000 Joule
Work done = 2 × 10^5 Joule
Here,
m is the mass of bus
v is the velocity of bus
s is the distance travelled by the bus
t is the time taken by bus
Hence,
2 × 10 ^5 joules is the work required to be done to stop a bus of mass 2000 kg moving at a velocity of
is the work required to be done to stop a bus of mass 2000 kg moving at a velocity of36km/h.
Answer:
-10^5
Explanation:
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