Calculate the work required to be done to stop a car 1500kg moving with velocity of 60m/h
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Hii There!!!
Given ,
m=1500kg
u= 60 km / h => 60 × 5/18 = 50/3m/s
v =0m/s ( its final velocity will be zero )
Since , W = Kf - Ki
KE = 1 / 2 mv²
W = 1 /2mv2 - 1/2 mu2
=> 1/2m(v2-u2)
=> 1/2 × 15000 [ 0- (50/3)2 ]
= -208333.33 Joules
Hence, required workdone = -208333.33 J
_____________________
# ¢'$ #
Hope it helps
Given ,
m=1500kg
u= 60 km / h => 60 × 5/18 = 50/3m/s
v =0m/s ( its final velocity will be zero )
Since , W = Kf - Ki
KE = 1 / 2 mv²
W = 1 /2mv2 - 1/2 mu2
=> 1/2m(v2-u2)
=> 1/2 × 15000 [ 0- (50/3)2 ]
= -208333.33 Joules
Hence, required workdone = -208333.33 J
_____________________
# ¢'$ #
Hope it helps
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