calculate the work required to be done to stop a car of 1200 kg moving with the velocity of 54 km per hour
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For the car,
mass= 1200kg
initial velocity, v=54km/hr
= 15m/s
final velocity,u= 0m/s
By work theorem,
work done= change in kinetic energy
therefore, W=∆K ( if you don't understand this line, ignore it)
therefore, W= 1/2mv^2 - 1/2mu^2
= 1/2 m (v^2-u^2)
=1/2*1200(0^2-15^2)
= 600(0-225)
= 600* (-225)
Therefore, Work= -135000J or -135 kj
Thus, the work required to stop the car is -135000Joule or -135 Kilo Joule.
The negative sign indicates that the work done is in the opposite direction.
mass= 1200kg
initial velocity, v=54km/hr
= 15m/s
final velocity,u= 0m/s
By work theorem,
work done= change in kinetic energy
therefore, W=∆K ( if you don't understand this line, ignore it)
therefore, W= 1/2mv^2 - 1/2mu^2
= 1/2 m (v^2-u^2)
=1/2*1200(0^2-15^2)
= 600(0-225)
= 600* (-225)
Therefore, Work= -135000J or -135 kj
Thus, the work required to stop the car is -135000Joule or -135 Kilo Joule.
The negative sign indicates that the work done is in the opposite direction.
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