calculate the work required to be done to stop a car of 1500 kg moving at a velocity of 50km/h
Answers
Answer:
=208.42kJ
Explanation:
Mass of the car = 1500 kg
Velocity = 50 km/hr =50x 5/18 = 13.8 m/s
Work done = change in kinetic energy
Work done = Final kinetic energy Initial kinetic energy
Required work done = 1/2 m v^2 1/2 m u^2
where,
final velocity, v = 0
initial velocity u = 13.8 m/s
Therefore,
work = (1/2 x 1500 x [(0)^2 (13.8)^2]) = 208413.81J = 208.42kJ
Answer: Mass of the car m = 1500 kg
Velocity of the car v = 60 km/h
= 60×1000 /60×60 = 50 /3 m/s
The car is in motion, so its energy = kinetic energy = 1 /2 mv2
= 1 /2 (1500) ( 50/ 3 ) 2 J
= 1/ 2 × (1500) × 2500/ 9 J
= 208333.3 J
The kinetic energy of the car, when it comes to rest = 0 J
Work done on object = change in kinetic energy
= 208333.3 − 0 J
= 208333.3 J
Hence, the work required to stop the car is 208333.3 J
Hope this helps you friend
Thanks ✌️ ✌️
Explanation: