Calculate the work required to be done to stop a car of 1500 kg moving at a velocity of 60 km/h ?
Answers
Answer:
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Explanation:
Solution: Kinetic energy, E k= 1/2 mv^2
Where,
Mass of car, m= 1500 kg
Velocity of car, v= 60 km/hr= (60 — 5 )/(18 ms^(-1) )
ˆ´ E k= 1/2 — 1500 — €–(60 — 5/18)€—^2 = 20.8 —€–10€—^4 J
Hence, 20.8 — 104 J of work is required to stop the car.
Answer:
here is ur answer
Explanation:
- Solution: Kinetic energy, E k= 1/2 mv^2
Where,
Mass of car, m= 1500 kg
Velocity of car, v= 60 km/hr= (60 — 5 )/(18 ms^(-1) )
ˆ´ E k= 1/2 — 1500 — €–(60 — 5/18)€—^2 = 20.8 —€–10€—^4 J
Hence, 20.8 — 104 J of work is required to stop the car.
another way to do:
When a object is moving with a constant velocity, it possess K.E
K.E= 21 ×m×v 2
So, in order to bring the object to rest i.e its same magnitude of energy is required so, as the final final energy comes to zero.
So, magnitude of work that needs to be done =
21 ×m×v 2
60km/hr=16.66m/s
So, work required to stop the car = 2 ×1500×16.66 2⇒=208166.7J=208.17kJ
(u can do with this way also)
here is ur answer
I hope it will help u