calculate the work required to be done to stop a car of 1500 kg moving at a velocity of 60 km h
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Answered by
12
m=1500kg
u= 60km/h =60* 5/18 = 50/3m/s
v =0m/s
w = change in its KE.
initial KE =1/2 mu2
final KE=1/2mv²
w = 1/2mv2 - 1/2 mu2
=1/2m(v2-u2)
= 1/2 * 15000{0- (50/3)2}
= -208333.33J
Answered by
5
heyy dear ur answer
Mass of car, m = 1500 kg
velocity, v = 60 km/h = 60×5/18=16.67m/s^2
Kinetic energy possessed by the car = 1/2 mv²
⇒ KE = 1/2×1500×16.67^2=20846.7j=208.4kj
To stop the car, we have to make the KE of car 0. So the work need to be done is 204.4 kJ............
hope this will help u............@kundan
Mass of car, m = 1500 kg
velocity, v = 60 km/h = 60×5/18=16.67m/s^2
Kinetic energy possessed by the car = 1/2 mv²
⇒ KE = 1/2×1500×16.67^2=20846.7j=208.4kj
To stop the car, we have to make the KE of car 0. So the work need to be done is 204.4 kJ............
hope this will help u............@kundan
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