Question

Calculate the work required to be done to stop a car of 1500 if moving at a speed of 60 km/h?

Answer 1

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GIVEN VALUES:-

m= 1500,

u= 60km/hr

u= 60X5/18

= 50/3m/s

= V=0

SOLUTION:-

w = change in its K.E. 

initial KE =1/2 mu²

 final KE=1/2mv²

W= final K.E. — initial K. E.

= 1/2mv²  - 1/2 mu²

=1/2m(v²-u²) 

= 1/2 * 15000{(0)²- (50/3)2}

$=  -208333.33J$

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Answer 2

heya...

Answer:

GIVEN VALUES:- 

m= 1500, 

u= 60km/hr 

u= 60X5/18 

= 50/3m/s 

= V=0 

SOLUTION:- 

w = change in its K.E. 

initial KE =1/2 mu²

 final KE=1/2mv²

W= final K.E. — initial K. E. 

= 1/2mv²  - 1/2 mu²

=1/2m(v²-u²) 

= 1/2 * 15000{(0)²- (50/3)2}

 =  -208333.33J \