Question

Calculate the work required to be done to stop a car of 1500 kg moving at a velocity of 60 km/h?​

Answer 1

m=1500kg u= 60km/h =60* 5/18 = 50/3m/s v =0m/s w = change in its KE. initial KE =1/2 mu2 final KE=1/2mv² w = 1/2mv2 - 1/2 mu2 =1/2m(v2-u2) = 1/2 * 15000{0- (50/3)2} = -208333.33J

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Answer 2

Hey there!

Given,

Mass of car (m) = 1500 kg

Velocity of car ( v) = 60 km/h = 60 * 5/18 m/s

Work done = ?

Here,

Work done = Kinetic Energy

                  = 1/2 * mv²

                  = 1/2 * 1500 * 60 * (5/18) J

                  = 20.8 × 10⁴ J (←Answer)

Hope It Helps You!