Calculate the work required to be done to stop a car of 1500kg moving with a velocity of 60 km/h?
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Answered by
2
Given:-
Mass of the car= 1500 kg
Velocity= 60 km/hr= 16.67 m/s
The force applied to stop the car would be calculated as:-
work done=change in kinetic energy
Thus, we have,
work done=Final kinetic energy - initial kinetic energy
Work done(required)= 1/2mv²- 1/2mu²
mass=m
velocity(v)=0
initial velocity(u)=16.67 m/s
Work=|1/2×1500×[(0)² - (16.67)²]
on calculating= 208416.68J
=208.42kJ
Hope this helps you!! :)
Mass of the car= 1500 kg
Velocity= 60 km/hr= 16.67 m/s
The force applied to stop the car would be calculated as:-
work done=change in kinetic energy
Thus, we have,
work done=Final kinetic energy - initial kinetic energy
Work done(required)= 1/2mv²- 1/2mu²
mass=m
velocity(v)=0
initial velocity(u)=16.67 m/s
Work=|1/2×1500×[(0)² - (16.67)²]
on calculating= 208416.68J
=208.42kJ
Hope this helps you!! :)
Answered by
0
I hope its helps you
Mass of the car= 1500 kg
Velocity= 60 km/hr= 16.67 m/s
The force applied to stop the car would be calculated as:-
work done=change in kinetic energy
Thus, we have,
work done=Final kinetic energy - initial kinetic energy
Work done(required)= 1/2mv²- 1/2mu²
mass=m
velocity(v)=0
initial velocity(u)=16.67 m/s
Work=|1/2×1500×[(0)² - (16.67)²]
on calculating= 208416.68J
=208.42kJ
Mass of the car= 1500 kg
Velocity= 60 km/hr= 16.67 m/s
The force applied to stop the car would be calculated as:-
work done=change in kinetic energy
Thus, we have,
work done=Final kinetic energy - initial kinetic energy
Work done(required)= 1/2mv²- 1/2mu²
mass=m
velocity(v)=0
initial velocity(u)=16.67 m/s
Work=|1/2×1500×[(0)² - (16.67)²]
on calculating= 208416.68J
=208.42kJ
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