Calculate the work required to be done to stop a car of 1500kg moving at a velocity of 60km/h?Q21. Why is it difficult for a fireman to hose, which ejects large amount of water at a high velocity?
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Explanation:
When a object is moving with a constant velocity, it possess K.E
K.E=21×m×v2
So, in order to bring the object to rest i.e its same magnitude of energy is required so, as the final final energy comes to zero.
So, magnitude of work that needs to be done =21×m×v2
60km/hr=16.66m/s
So, work required to stop the car =21×1500×16.662
⇒=208166.7J=208.17kJ
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