Calculate the work required to be done to stop a car of 1500kg moving at a velocity of 72km/hr
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Answered by
1
Work done = Change in Kinetic energy
Change in kinectic energy= kinetic energy while moving - kinetic energy while stopped
U = Initial velocity = 72 km / hr
V = Final velocity = 0 Km / hr
Change in K.E. = 1/2 mu² - 1/2mv²
= 1/2m ( u² - v²)
= 1 / 2 * 1500 ( 72² - 0² )
= 750 ( 72²)
= 750 * 5184 = 3888000 J = 3888 KJ
Hope it helps!!
Cheers!!
Change in kinectic energy= kinetic energy while moving - kinetic energy while stopped
U = Initial velocity = 72 km / hr
V = Final velocity = 0 Km / hr
Change in K.E. = 1/2 mu² - 1/2mv²
= 1/2m ( u² - v²)
= 1 / 2 * 1500 ( 72² - 0² )
= 750 ( 72²)
= 750 * 5184 = 3888000 J = 3888 KJ
Hope it helps!!
Cheers!!
Steph0303:
ok??
http://www.examfear.com/question/986/detail.htm
check on this website
they converted 60 km/hr in m/s first
i have taken it as km/hr itself
yes but they convert 60 km/hr into 60 m/s
ok.. i got it
thx
ok
o mthats why i convrted to kj
Answered by
0
m=1500kg
u= 60km/h =60* 5/18 = 50/3m/s
v =0m/s
w = change in its KE.
initial KE =1/2 mu2
final KE=1/2mv²
w = 1/2mv2 - 1/2 mu2
=1/2m(v2-u2)
= 1/2 * 15000{0- (50/3)2}
= -208333.33J
I wish this helps u : )
u= 60km/h =60* 5/18 = 50/3m/s
v =0m/s
w = change in its KE.
initial KE =1/2 mu2
final KE=1/2mv²
w = 1/2mv2 - 1/2 mu2
=1/2m(v2-u2)
= 1/2 * 15000{0- (50/3)2}
= -208333.33J
I wish this helps u : )
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