Calculate the work required to be done to stop a car of 1200kg moving at a speed of 54km/h
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For the car,
Mass, m = 1200 kg
Initial Velocity, u = 54 km/h = 15 m/s
Final velocity, v = 0m/s
By Work Energy Theorem,
Work Done=Change in Kinetic Energy
∴W = ΔK (If you don't understand this line, ignore it)
∴W = 1/2 mv² - 1/2 mu²
= 1/2 m (v² - u²)
= 1/2 * 1200 (0² - 15²)
= 600 (0-225)
= 600 * -225
∴W = -135,000 J or -135 kJ
Thus the Work required to stop the car is -135,000 Joule or -135 kilo Joule.
The negative sign indicates that the work done is in the opposite direction.
Mass, m = 1200 kg
Initial Velocity, u = 54 km/h = 15 m/s
Final velocity, v = 0m/s
By Work Energy Theorem,
Work Done=Change in Kinetic Energy
∴W = ΔK (If you don't understand this line, ignore it)
∴W = 1/2 mv² - 1/2 mu²
= 1/2 m (v² - u²)
= 1/2 * 1200 (0² - 15²)
= 600 (0-225)
= 600 * -225
∴W = -135,000 J or -135 kJ
Thus the Work required to stop the car is -135,000 Joule or -135 kilo Joule.
The negative sign indicates that the work done is in the opposite direction.
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