Question

Calculate the work required to be done to stop a car of 1500kg moving at a velocity 0f 36 km/h​

Answer 1

Answer:

Solution:

Explanation:

Data:

m=1500kg

v=36km/h=10m/s

W=?

Solution:

Formula=> Work=∆K.E

K.Ei = 1/2mv^2

K.Ei= 1/2(1500)(10)^2

K.Ei = 75,000J

Since bidy comes to rest then;

K.Ef= 0J

According to Formula,

W = 75000-0

W= 75000J

Answer 2

Given, Speed of the Car $= 36km/hr$

Mass of the Car $= 1500Kg$

Now, We have to find the minimum work which is required to stop the car.

We know that,

When an object moves at a constant speed, it has K.E.

$K.E = \frac{1}{2}mv^{2}$

So, as the object's final energy decreases to zero, the same amount of energy is needed to bring the object to rest.

$v=36km/hr = 10m/s$

Therefore, the amount of work that must be done $=\frac{1}{2}mv^{2}$

The effort needed to stop the vehicle $=\frac{1}{2} *1500*(10)^{2} = 75000.0J = 75kJ$

Hence, the minimum work required to stop the car is $75kJ$

For more such questions on Velocity: https://brainly.in/question/32406047

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