Question

Calculate the work required to be done to stop a car of 1500kg moving at a velocity of 60km\h?

Answer 1

1. Given,

Initial velocity (v) = 60 km/h-square

$60 \times 5 \div 18 = 30 \div 3$

Work done = Loss in kinetic energy

Initial kinetic energy - Final kinetic energy

1/2(mv)square - 0 = 1/2(mv) square

1/2×1500kg × 50/30ms-square

208333.3J

2.08 × (10)square 5 J