Question

Calculate the work required to be done to stop an object of 40 kg moving at a velocity of 36 km/h

Answer 1

To stop the object the work required to be done is 2 kJ

Explanation:

Given mass of object, m = 40 kg

Velocity of an object, u = 36 km =36 × 5/18 = 10 m/s

Required work done = change in kinetic energy

$W =\frac{1}{2}mv^{2} -\frac{1}{2}mu^{2}$

Here v is final velocity.

Substitute the given values, we get

$W =\frac{1}{2} 40(0)-\frac{1}{2}40(10 m/s)^{2}$

W =-2000 J = - 2 kJ.

Thus, to stop the object the work required to be done is 2 kJ.

Learn more:  work done

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