calculate the work required to be done to stopa car of 1500 kg movin with velocity of 60 km/hr
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Answered by
1
Now Work Done = change into kinetic energy.
Now Work Done = 1/2m(v2 - u2)
=1/2×1500 { (0) -(60)²}
=750× -3600
= -2700000 J = -2700 KJ
Now Work Done = 1/2m(v2 - u2)
=1/2×1500 { (0) -(60)²}
=750× -3600
= -2700000 J = -2700 KJ
Answered by
0
Mass of car, m = 1500 kg
velocity, v = 60 km/h = 60 \times \frac{5}{18}=16.67\ ms^{-1}
Kinetic energy possessed by the car = \frac{1}{2} mv²
⇒ KE = \frac{1}{2} \times 1500 \times 16.67^2=208416.7\ J=208.4\ kJ
To stop the car, we have to make the KE of car 0. So the work need to be done is 204.4 kJ.
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