calculate the work required to stop the car of 1500kg moving at a speed of 72km/h by applying brakes.
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We should apply work-Energy theorem to find out the work ( say W) required to stop the Car by applying brakes .
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initial speed of the car = 72Km/h
= 72×(5/18) = 20m/s
=> KE (initial) = ½×(1500)×(20)²
= 300000J .
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final speed = 0 m/s
( Car has came to rest )
=> KE (final) = 0 J
_________________
Further ;
Applying W-E theorem :
W = KE(final) - KE (initial)
=> W = -300000J
__________________
hope it helps !
_________________
initial speed of the car = 72Km/h
= 72×(5/18) = 20m/s
=> KE (initial) = ½×(1500)×(20)²
= 300000J .
------
final speed = 0 m/s
( Car has came to rest )
=> KE (final) = 0 J
_________________
Further ;
Applying W-E theorem :
W = KE(final) - KE (initial)
=> W = -300000J
__________________
hope it helps !
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