Question

Calculate the workdone by a man carrying a load of 100kg over his head through a distance of 20m in vertical and 50m in horizontal direction?

Answer 1

Answer:

in horizontal direction = 0

in vertical direction = 19620J

Explanation:

in horizontal direction there is no change in Kinetic or Potential Energy therefore no work is done.

In vertical direction work done = mgh

= 100 * 9.81 * 20

= 19620J