Calculate the workdone by a man carrying a load of 100kg over his head through a distance of 20m in vertical and 50m in horizontal direction?
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Answer:
in horizontal direction = 0
in vertical direction = 19620J
Explanation:
in horizontal direction there is no change in Kinetic or Potential Energy therefore no work is done.
In vertical direction work done = mgh
= 100 * 9.81 * 20
= 19620J
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