Chemistry, asked by Lvina4095, 1 year ago

Calculate the wt of co having the same no of oxygen atoms as are present in 22g co2

Answers

Answered by deepzzzps
0

Molar mass CO2 = 44 g/mol 

You have 22g , so you have 22/44 = 0.5 mol CO2 

1mol CO2 has 6.022*10^23 molecules 

0.5mol CO2 has (6.022*10^23)*0.5 = 3.011*10^23 molecules 

1molecule of CO2 contains 2 atoms of O 

Therefore, 3.011*10^23 molecules of CO2 will contain (3.011*10^23) *2 = 6.022*10^23 atoms O

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