calculate the x by pythagoras's theorem.
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Lets take points on the given diagram
Now the given diagram has 3 right triangles :-
- ∆BAE let it be ∆₁
- ∆EBC let it be ∆₂
- ∆ECD let it be ∆₃
☯ Pythagoras theorem :-
Square of hypotenuse equal to Sum of square of base and height of right triangle
→ Hypotenuse² = Base² + Height²
♦ ∆₁ :-
- Hypotenuse = ?
- Base = 1 cm
- Height = 1 cm
Using Pythagoras theorem
⇒ Hyp² = 1² + 1²
⇒ Hyp² = 1 + 1
⇒ Hyp = √2 cm
♦ ∆₂ :-
- Hypotenuse = ?
- Base = Hypotenuse of ∆₁ = BE = √2cm
- Height = √2cm
⇒ Hyp² = (√2)² + (√2)²
⇒ Hyp² = 2 + 2
⇒ Hyp = √4 = 2 cm
♦ ∆₃ :-
- Hypotenuse = x cm = ?
- Base = Hypotenuse of ∆₂ = CE = 2cm
- Height = √5 cm
⇒ Hyp² = 2² + (√5)²
⇒ Hyp² = 4 + 5
⇒ Hyp = √9 = 3 cm = x cm
☯ x = 3 cm
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hope.. it help..
thanku..
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