Math, asked by HarshFatak, 28 days ago

calculate the x by pythagoras's theorem.​

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Answers

Answered by ItzArchimedes
49

Lets take points on the given diagram

Now the given diagram has 3 right triangles :-

  • ∆BAE let it be ∆₁
  • ∆EBC let it be ∆₂
  • ∆ECD let it be ∆₃

Pythagoras theorem :-

Square of hypotenuse equal to Sum of square of base and height of right triangle

→ Hypotenuse² = Base² + Height²

:-

  • Hypotenuse = ?
  • Base = 1 cm
  • Height = 1 cm

Using Pythagoras theorem

⇒ Hyp² = 1² + 1²

⇒ Hyp² = 1 + 1

⇒ Hyp = √2 cm

∆₂ :-

  • Hypotenuse = ?
  • Base = Hypotenuse of ∆₁ = BE = √2cm
  • Height = √2cm

⇒ Hyp² = (√2)² + (√2)²

⇒ Hyp² = 2 + 2

⇒ Hyp = √4 = 2 cm

∆₃ :-

  • Hypotenuse = x cm = ?
  • Base = Hypotenuse of ∆₂ = CE = 2cm
  • Height = √5 cm

⇒ Hyp² = 2² + (√5)²

⇒ Hyp² = 4 + 5

⇒ Hyp = √9 = 3 cm = x cm

x = 3 cm

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Answered by Anonymous
12

hope.. it help..

thanku..

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