Question

Calculate the zeros of the polynomial p(x)=4x2-12x+9

Answer 1

p(x) = 4x^2 - 12x + 9

= 4x^2 - 6x - 6x + 9

p(x) = 2x(2x - 3) - 3(2x - 3)

0 = (2x - 3)(2x - 3)

Therefore

$\tt Zeroes\:are = \dfrac{3}{2} , \dfrac{3}{2}$

$\tt x = \dfrac{3}{2}, \dfrac{3}{2}$

Hence zeroes of polynomial are :-

$\tt \dfrac{3}{2}, \dfrac{3}{2}$

Answer 2

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