Question

Calculate thew mass of nitrogen supplied to the soil by 5Kg of urea. [CO(NH2)2] ?

Answer 1

Molar Mass of Urea = 60

Mass of Nitrogen in 60 g of urea = 28g
Mass of Nitrogen in 5000g fof urea = $28 \times \frac{5000}{60} = 2333.33g  =2.3333 kg$

Answer 2

Answer:

moles of urea = 5000/60

moles of nitrogen = 2×500/6×14

mass of nitrogen = 2×500/6×14

= 2333.3gm