Question

Calculate time taken by an object moving with velocity of 12m/s and reduces it's speed to 7m/s by covering distance of 1.2km​

Answer 1

Explanation:

List the known and unknown quantities from the question.

u = initial velocity = 20 m/s

v = final velocity = 25 m/s

a = acceleration = 1.8 m/s² (not needed)

t = time interval = 5 s

s = displacement = ? m

Use the following kinematic equation to calculate the displacement.

s = (u + v)/2 × t

s = (20 m/s + 25 m/s)/2 × 5 s = 112.5 m

$\huge \underbrace \mathfrak \red{Pls follow꧂}$

Answer 2

Answer:

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