calculate time taken by electron to complete 10 revolution in hydrogen atom
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we know that time= distance by speed
radius of a hydrogen orbit is .529x10^-9 m/s
distance =circumference of orbit=2x3.14x.529x10^-9
=3.32x10^-9m
for ten revolution it will be 3.32x10^-8m
velocity of electron is 2.18x10^6m/s
therefore time taken = (3.32x10^-8)/(2.18x10^6)
=1.522x10^-14 secs
radius of a hydrogen orbit is .529x10^-9 m/s
distance =circumference of orbit=2x3.14x.529x10^-9
=3.32x10^-9m
for ten revolution it will be 3.32x10^-8m
velocity of electron is 2.18x10^6m/s
therefore time taken = (3.32x10^-8)/(2.18x10^6)
=1.522x10^-14 secs
shreysinghal78oud901:
Dude can you recheck? Cuz my answer came out to be 1.52*10^-15 m/s n I used a calculator.
***seconds not m/s xD
The radius is .529Å = .529 * 10^-10 m
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Answer = 1.52*10^-15 seconds.
Answer = 1.52*10^-15 seconds.
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