Question

calculate tje percentage composition of lead in lead nitrate ......Pb=207,N=14,O=16 ,C=12,H=1.​

Answer 1

Mol. formula of lead nitrate __ Pb(NO3)2

Rel. mol. mass of lead nitrate is 207 + ( 14+ 3*16)*2 = 331 a.m,u

gra. mol. mass of lead nitrate is 331g

percentage of lead present is 207/331 * 100 = 0.625* 100

                                                                          =62.5%