Chemistry, asked by Aru18angrybird, 1 year ago

calculate tje percentage composition of lead in lead nitrate ......Pb=207,N=14,O=16 ,C=12,H=1.

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Answered by arnavlokhande13

5

Mol. formula of lead nitrate __ Pb(NO3)2

Rel. mol. mass of lead nitrate is 207 + ( 14+ 3*16)*2 = 331 a.m,u

gra. mol. mass of lead nitrate is 331g

percentage of lead present is 207/331 * 100 = 0.625* 100

=62.5%

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