Calculate total charge on 48 g of SO42– ion. (A) 1.6 × 10–19 C (B) 3.2 × 10–19 C (C) 4.8 × 10–19 C (D) 6.4 × 10–19 C
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Answer:
3.86×10 ^5C
Molar mass of Mg +2=24g
Given mass of Mg +2 =48g
No. of moles of Mg +2= Molar mass
Given mass = 24^48 =2 moles1 mole of Mg +2= 2 moles of electrons
∴2 moles of Mg +2= 4 moles of electrons
∴ No. of electrons = no. of moles of electronsAvogadro's constant
⇒ No. of electrons =4×6.023×10 ^23 =2.4×10 ^24
As we know that,
Charge on 1 electron =1.6×10 −19 C
∴ Total charge on 48 g Mg +2
=no. of e − s×charge on 1 e −
=(2.4×10 ^24 )×(1.6×10 −19 )=3.84×10 ^5
C≈3.86×10 ^5C
Hence, the correct answer is 3.86×10^5C.
Explanation:
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