Calculate Total effective resistance
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Answer:
1. Total effective resistance of the circuit, R = R1 + R23 = 20 + 20 = 40.
2.Since 20 Ω is in series in the circuit, the current remains the same, i.e., 0.25 A.
Explanation:
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Answer:
let 4Ω resistance be R1 nad 2Ω be R2 and 6Ω be R3.
Explanation:
now,
=R1+R2=4+2=6Ω=Rp (connected in series.)
=Now Rp and R3 are connected in parallel.
∴1/6+1/6=2/6
∴Resultant resistance=6/2=3Ω
Ans=3Ω
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