Question

calculate total heat absorbed in joules for the conversion of 100g water at 95*C to steam at 100*C(sp heat of water 4180 J/Kg/*C)

Answer 1

Answer:

To raise the temperature of the water from 95 degrees Celsius to 100 degrees Celsius requires an energy input of:

5×4200×0.1

=2100 J

The energy required to turn water into steam is given by its heat of vaporization, which is 2257 J/g . This means the energy input will have to be:

2257×100

=225700 J

Therefore, the total energy required will be:

2100+225700

=227800 J

Which equals 54445.5067 calories .

Explanation:

54445.5067 calories .

Answer 2

Answer:

To raise the temperature of the water from 95 degrees Celsius to 100 degrees Celsius requires an energy input of:

5×4200×0.1  

=2100   J  

The energy required to turn water into steam is given by its heat of vaporization, which is  2257   J/g . This means the energy input will have to be:

2257×100  

=225700   J  

Therefore, the total energy required will be:

2100+225700  

=227800   J  

Which equals  54445.5067   calories .

Explanation: