calculate total no. of atoms in 222 gm of CaCl2
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111gm CaCl2 contain 6.022× 10^23 atoms
so 222gm CaCl2 will contain
=6.022×10^23×222/111
=12.044×10^23 atoms.
please mark it as brainliest.
so 222gm CaCl2 will contain
=6.022×10^23×222/111
=12.044×10^23 atoms.
please mark it as brainliest.
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