Question

Calculate total no. of neutrons present in 1.7 g ammonia

Answer 1

Hello Dear.

Here is your answer---


In one atom of ammonia, 
 Number of Electrons = 10
 Number of Protons = 10
 Number of Neutrons = Mass Number - Atomic Number
                                  = 17 - 10
                                  = 7 Neutrons.

Given---
      Mass of Ammonia = 1.7 grams.
   Molecular mass of Ammonia = 17 grams.

Number of Atoms  = (Mass/Molecular mass)  × Avogadro's Number(NA)
                              = (1.7/17) × Avogadro's Number
                              = 0.1 × Avogadro's Number
                             = 0.1 Na

∵ one atom of Ammonia contains 7 Neutrons.
∴, 0.1 Na ---------------------------------- 7 × 0.1 Na
                                                        = 0.7 Na
                                                        = 0.7 × Na
Since Na = 6.022 × 10²³
Thus, Number of Neutrons = 0.7 × 6.022 × 10²³
                                           =  4.2154 × 10²³ Neutrons.


→→→→→→→→→→


Hope it helps.

Have a Marvelous Day.

Answer 2

Answer:

Hi ! your answer is as follows. If you wish please make it in a brain list. It is in terms of avagadro number. Have a great day