Question

calculate total number of atom present in 9 gram of water.
please full explanation and step by step.

Answer 1

TOTAL ATOM PRESENT IN 9 GRAMS OF WATER
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➡ WEIGHT OF WATER = 18 g/mol

➡ NUMBER OF ATOMS = 9 × 18

➡ NUMBER OF ATOMS = 162
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➡ HOPE IT HELPS

➡ HAVE A NICE DAY MY FRIEND

Answer 2

Answer :

given :

The molecular weight = $H_{2} O$

                                      => 2 x 1 x 16

                                      => 18 Gram

Total molecules present in 18 gram water = ?

1 mol water has 2 mol hydrogen and 1 mol oxygen atom

           1 mol water = 18 gram water

therfore

18 gram $H_{2} O$ Has = 2 mol hydrogen atom

                                                     

=> 2 x 6.022 x$10^{23}$

                                                   

  => 12.044 x $10^{23}$

18 gram $H_{2}O$ Has = 1 mol oxygen atom

                                                   

=> 1 x 6.022 $10^{23}$

hence ,

             18 gram $H_{2}0$ Has total atoms

                       

 => 12.044 x  $10^{23}$ + 6.022 x $10^{23}$

                         

 => 18.066 x $10^{23}$

18 gram water has total atoms = 18.066 x  $10^{23}$

9 gram water has total atoms

= 18.066  x 9 x 10^23 / 18

                                                 

 => 9.033 $10^{23}$ atoms