Question

Calculate total number of electrons present i in 6.4 g of Sulphur dioxide?​

Answer 1

Weight of S =6.4 g

Atomic weight of S =32 g/g atom

Number of gram atoms of S =

32 g/gatom

6.4 g

=0.2 gram atoms.

The Avogadro's number is 6.023×10 ²³atoms/ g atom

The number of atoms of S =0.2 gram atoms ×6.023×10²³atoms/ g atom

=1.2×10²³ atoms.

I hope you got your answer.

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Answer 2

Weight of S = 6.4 g

Atomic weight of S =32 g/g atom

Number of gram atoms of S

$= \frac{6.4g}{32g/gatom} = 0.2 \: gram \: atom.$

The Avogadro's number is

$6.023 \times {10}^{23} atoms/g \: atom$

The number of atoms of S

$= 0.2 \: gram \: atom \times 6.023 \times {10}^{23} \: atoms/g \: atom</p><p></p><p>= 1.2 \times {10}^{23} atoms$