Question

Calculate total number of O2 atoms in a container which have 110g of CO2 , 90g of H2O , 160 g of SO3 and 342g of sucrose

Answer 1

Answer:

Explanation:

carbon dioxide is CO2 so each molecule has 2 oxygen atoms so one  mole of co2 is  having 2 moles of oxygen atoms now  

molar mass of co2 =44 grams so in 110  grams has 110/44 which is 2.5 moles of co2 so 2.5x2=5 moles of oxygen atoms  

ozone is O3 having 3 oxygen  atoms so one mole ozone is 3 moles of oxygen atoms  

molar mass of ozone = 16x3= 48 grams now in 96 grams ,96/48=2 moles of ozone so 2x3=6moles of oxygen atoms  

water h20 has one oxygen so one mole of water has one mole of oxygen atoms  

molar mass=18 g so 90 grams has 90/18=5 moles of water so 5x1 =5 moles of oxygen atoms

sulphur trioxide SO3 has 3 oxygen atoms one mole so3 has 3 moles oxygen atomns

molar mass of sulphur trioxide =32+16x3=80 so  160/80 = 2moles  now 2 x3=6 moles of oxygen atoms

sucrose c12h22o11 has 11 oxygen atoms so one mole sucrose has 11 mole oxygen atoms  

molar mass of ucrose is 342 so 342/342 =1 mole so 1x11=11mole oxygen atoms \

now adding all 5+6+5+6+11=33 moles now each mole of any thing has avogadro number that is 6.022x10^23 number of entities or atoms or molecules so

33x6.022x10^23 which is 198.7x10^23 number of oxygen atoms  

easy but a long one hopoe u undrerstiood it!